On February 23 and February 25 we showed a total of 27 + 31 = 58 numbers that factor into significant integers: 2, 3, 5, 7, 10, 11, 12, 13, 17, 23, 37, 40, and 43. On the last post, February 28, we codified the data. We now factor 99 random numbers between 17 and 13000 and see how many times we get our significant numbers. The integers below were generated and factored on Sunday, March 1, 2009 at 8:20 A.M. (CST) . Those numbers underlined denotes those that factor into our significant integers.
10518 = 2 3 1753 9302 = 2 4651 4340 = 2^2 5 7 31 (1
9052 = 2^2 31 73 1345 = 5 269 5915 = 5 7 13^2 (2
3261 = 3 1087 7747 = 61 127 8173 = 11 743 (3
2084 = 2^2 521 4714 = 2 2357 10625 = 5^4 17 (4
5838 = 2 3 7 139 10786 = 2 5393 6838 = 2 13 263 (5
5785 = 5 13 89 9689 = 9689 10703 = 7 11 139 (6
10019 = 43 233 12184 = 2^3 1523 10644 = 2^2 3 887 (7
4383 = 3^2 487 10038 = 2 3 7 239 6664 = 2^3 7^2 17 (8
3842 = 2 17 113 5830 = 2 5 11 53 782 = 2 17 23 (9
3555 = 3^2 5 79 2663 = 2663 4668 = 2^2 3 389 (10
3519 = 3^2 17 23 6237 = 3^4 7 11 7135 = 5 1427 (11
10150 = 2 5^2 7 29 1755 = 3^3 5 13 1300 = 2^2 5^2 13 (12
1794 = 2 3 13 23 3267 = 3^3 11^2 8852 = 2^2 2213 (13
3365 = 5 673 12275 = 5^2 491 10959 = 3 13 281 (14
12796 = 2^2 7 457 11217 = 3 3739 2914 = 2 31 47 (15
6131 = 6131 9881 = 41 241 5232 = 2^4 3 109 (16
4917 = 3 11 149 3382 = 2 19 89 9638 = 2 61 79 (17
953 = 953 6669 = 3^3 13 19 515 = 5 103 (18
3665 = 5 733 4050 = 2 3^4 5^2 7440 = 2^4 3 5 31 (19
9927 = 3^2 1103 1387 = 19 73 9189 = 3^2 1021 (20
10391 = 10391 10976 = 2^5 7^3 12798 = 2 3^4 79 (21
10149 = 3 17 199 7867 = 7867 9972 = 2^2 3^2 277 (22
241 = 241 12622 = 2 6311 5005 = 5 7 11 13 (23
4223 = 41 103 12773 = 53 241 4797 = 3^2 13 41 (24
7086 = 2 3 1181 7656 = 2^3 3 11 29 3083 = 3083 (25
12562 = 2 11 571 11266 = 2 43 131 5695 = 5 17 67 (26
8589 = 3 7 409 2771 = 17 163 1472 = 2^6 23 (27
3786 = 2 3 631 1862 = 2 7^2 19 8742 = 2 3 31 47 (28
7721 = 7 1103 7763 = 7 1109 12137 = 53 229 (29
9601 = 9601 560 = 2^4 5 7 4897 = 59 83 (30
5015 = 5 17 59 6101 = 6101 6151 = 6151 (31
9430 = 2 5 23 41 3205 = 5 641 6930 = 2 3^2 5 11 (32
7217 = 7 1031 2517 = 3 839 1277 = 1277 (33
Timestamp: 2009-03-01 14:20:17 UTC
Below are the only integers, N, that factored into our significant numbers.
5915 = 5 7 13^2 10625 = 5^4 17 6664 = 2^3 7^2 17 (1
782 = 2 17 23 3519 = 3^2 17 23 6237 = 3^4 7 11 (2
1755 = 3^3 5 13 1300 = 2^2 5^2 13 1794 = 2 3 13 23 (3
3267 = 3^3 11^2 4050 = 2 3^4 5^2 10976 = 2^5 7^3 (4
5005 = 5 7 11 13 1472 = 2^6 23 560 = 2^4 5 7 (5
6930 = 2 3^2 5 7 11 (6
We have only about 16% or sixteen out of 99 numbers that factor into our significant integers. The highest number is 23; we have no factors of 37, 40 and 43. We have mostly the lower numbers: 2 and 3 and 5, which is what we'd expect. Suppose we have a grab bag full of integers and we blindly reach in and grab one (denote as N). Since every other number is divisible by n = 2, we'd have a 50% chance that our number N is divisible by 2. Since every third number is divisible by n = 3, we have a 33% chance that our number N is divisible by 3. So for any number N, the higher the significant number n, the less chance we have that n will divide N. Therefore we aren't surprised not to have drawn any numbers divisible by our significant numbers n where n = 37, 40, or 43.
We can compare the above 99 numbers to 33 poker games with three players represented by the three columns. Player number 1, (the first column) had only two winning hands. Player number 2 (second column) had six winning hands. Player number 3 (third column) had eight winning hands (2 + 6 + 8 = 16) and went home the winner. But out of these 33 games they together only had 16 winning hands and 83 losing hands.
Suppose now that the next night they play 57 games. Everyone calls player number 3 V.I. for village idiot. What if out of these 57 games V.I. pulls 57 winning hands. The previous night they together pulled a total of 16 winning hands out of 33 games and 99 hands. Suppose V.I. pulls a 43 for 19% of the deals, a 37 for 15% of the deals and a 23 for 20% of the deals (see February 28). The previous night the numbers 37 and 43 never even showed up in 99 hands. How long would it take player number 1 and number 2 to suspect that V.I. only wants everyone to think he's an idiot? By the same token how long does it take before we suspect those 57 numbers listed on February 28 were rigged?
So who rigged those fifty-seven numbers? Those who wrote the Bible? That would mean they had to arrange events and define the "correct" number of years between them. Thus they would have favored what adds up rather than what's historically correct. But as of this writing, I know of only one discrepancy between Scripture and the secular dating: the year B.C. 722 and the Biblical one: B.C. 709 for the Assyrian destruction of Israel.
No one knew the timeline until the latter half of the last century. How could anyone have rigged those numbers if they didn't know what they were? What's that? I rigged them? Here, search me: Contents: Part 2. See if I didn't get them straight out of the Bible.
We complete Part three on Saturday, March 4.